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Anonymous286:
inclination 30 hai ya 37
inclination is 30
toh woh 37 kya diya hai?
I think mistake hogi we should consider what is written in the question
ohk
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So firstly draw fbd
The fbd is in the attachment
after FBD write the equations
mgsin30-f=ma
Since block doesn't slip
mgsin30-f=0
mgsin30 =f
but f=uN
mgsin30=uN
but N =mgcos30+F
Hence
mgsin30=u(mgcos30+F)
mg=mgcos30+F
F=mg-√3mg/2
=0.134mg
=0.134*2*9.8
=2.6290N
Note:Always before starting such sums give a check of angle of repose
Hope it helps
The fbd is in the attachment
after FBD write the equations
mgsin30-f=ma
Since block doesn't slip
mgsin30-f=0
mgsin30 =f
but f=uN
mgsin30=uN
but N =mgcos30+F
Hence
mgsin30=u(mgcos30+F)
mg=mgcos30+F
F=mg-√3mg/2
=0.134mg
=0.134*2*9.8
=2.6290N
Note:Always before starting such sums give a check of angle of repose
Hope it helps
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just let me know if this is correct or not?
the correct answer is 8N
pata nahi kya wrong ho raha hai
ek toh question me bhi error hai
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