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Hope it would help u
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shubham6023:
thanks bro
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Step-by-step explanation:
√6x+7 + (2x+3) = 0
Sq both sides
6x + 7 + 4x^2 + 12x + 9 = 0
4x^2 + 18x + 16 = 0
2x^2 + 9x + 8 = 0
=> a=2, b=9 & c=8
=> b^2 -4ac = 9^2 - 4(2)(8) = 81 - 64 = 17
=> x = (-b+√b^2 -4ac)/2a or (-b-√b^2-4ac)/2a
=> x = (-9+√17)/4 or (-9-√17)/4
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