Question

answer this question

Answer 1

Hope it would help u

Answer 2

Step-by-step explanation:

√6x+7 + (2x+3) = 0

Sq both sides

6x + 7 + 4x^2 + 12x + 9 = 0

4x^2 + 18x + 16 = 0

2x^2 + 9x + 8 = 0

=> a=2, b=9 & c=8

=> b^2 -4ac = 9^2 - 4(2)(8) = 81 - 64 = 17

=> x = (-b+√b^2 -4ac)/2a or (-b-√b^2-4ac)/2a

=> x = (-9+√17)/4 or (-9-√17)/4