Question

answer this question 8 only

Answer 1

HEY DEAR....
HERE'S YOUR ANSWER⬇

=> Let us assume : x= root(6+root(6 + root(6 + ………

So,

# x= root(6+x)

# x^2=6+x

# x^2-x-6=0

# (x-3)(x+2)=0

So, x=3 or -2.

But taking -2 as the answer would mean we are taking root of (-2) . Considering the fact that x belongs to the set of real numbers , we discard the solution x=-2.

So the answer is x =3.
Any doubts, please ask me in the comments.
I HOPE YOU FIND IT HELPFUL.
@ LB :)