Question

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Answer 1

${x}^{2} + 2x + 4p = 0$

${( - 4)}^{2} + 2 \times (- 4) + 4p = 0$

16 - 8 + 4p = 0

8 + 4p = 0

4p = -8

p = -8/4

$p = - 2$

${x}^{2} + px(1 + 3k) + 7(3 + 2k) = 0$

${( - 4)}^{2} + ( - 2)( - 4)(1 + 3k) + 7(3 + 2k) = 0$

16 + 8(1+3k) + 7(3+2k) = 0

16 + 8 + 24k + 21 + 14k = 0

(16 + 8 + 21) + (24k + 14k) = 0

45 + 38k = 0

38k = -45

$k \: = \frac{-45}{38}$

Hope it helps.

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