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Given sin 2A = cos(3A - 45)
(:sinA = cos (90 - A) )
by problem :
cos (90-2A ) = cos(3A-45 )
cos gets cancelled
90 - 2A = 3A - 45
=90 + 45 = 3A + 2A
=135 = 5A
A = 135 / 5
A = 27
(:sinA = cos (90 - A) )
by problem :
cos (90-2A ) = cos(3A-45 )
cos gets cancelled
90 - 2A = 3A - 45
=90 + 45 = 3A + 2A
=135 = 5A
A = 135 / 5
A = 27
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