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GIVEN: a =3 and d=3
So, An=a+(n-1)d
PUt the values
n=100
WE GET
A(100)= 3+99*3
=300
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AP:--3,6,9,......
a=3 d=6-3=3
T100=a+(n-1)d
T100=3+(100-1)3
T100=3+99 x 3
T100 =3+ 297
T100=300
a=3 d=6-3=3
T100=a+(n-1)d
T100=3+(100-1)3
T100=3+99 x 3
T100 =3+ 297
T100=300
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