Question

answer this question ​

Answer 1

Answer:

Step-by-step explanation:

let AC be the diameter

quadrant=Ф/360πr²

              =90/360*22/7*8*8

              =352/7cm²

area of ΔADC=1/2bh

                      =1/2*8*8

                      =32cm²

area of shaded region=(352/7)-32

                                     =(352-224)/7

                                     =128/7cm²

area of design =2*128/7

                         =36.57cm²

hope it helps

Answer 2

S^2 = 8

S = 64

Theta/ 360 x pie x r x r

90/360 x 22/7 x 8 x 8

= 96/7

96/7 x 2 = 256/7

Therefore 256/7 is the area of the design.