Question

Answer this question according to class 8..



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Remember answer according to class 8.



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Answer 1

Answer:

During upstream

t1= s/(vm - vr)

t1= s/3

During downstream

t2= s/(vm+vr)

t2= s/5

now,total time

t= t1+t2

0.8= s/3 + s/5

0.8= s(3+5)/15

8s= 12

s= 3/2

s= 1.5

he goes 1.5 km upstream.

hope it helps u

BRAINLIST

Answer 2

Hello Mate,

Here is your answer in a more simpler method,

Given:

$v_{1} = 5kmph \\ \\ u_{2} = 3kmph \\ \\ total \: time = 48min \\ \\ = 0.8hrs$

To Find:

Distance traveled upstream

We Know,

$t = \frac{d}{v}$

So,

$t_{1} = \frac{d}{5} \\ \\ t_{2} = \frac{d}{3}$

As given that,

$t_{1} + t_{2} = 0.8$

So,

$\frac{d}{5} + \frac{d}{3} = 0.8 \\ \\ \frac{3d + 5d}{15} = 0.8 \\ \\ 8d = 15 \times 0.8 \\ \\ 8d = 12 \\ \\ d = \frac{12}{8} \\ \\ d = \frac{3}{2} \\ \\ d = 1.5km$

Hence the distance traveled upstream (d) is equal to 1.5 kilometers

Hope it helps:)

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