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p (x) = 2x3 + x2 - 5x + 2
Now if we take x = 1/2 then
p(1/2) = 2 × (1/2)3 + (1/2)2 - 5 × 1/2 + 2
= 2 × 1/8 + 1/4 - 5/2 + 2
= 1/4 + 1/4 - 5/2 + 2
= 1/4 + 1/4 - 10/4 + 4/4
= -4/4
= -1
Now taking p(x) = 1
p(x) = 2 × (1)3 + (1)2 - 5 × 1 + 2
= 2 + 1 -5 + 2
= 3 - 5 + 2
= -2 + 2
= 0
Now taking p(×) = -2
p(x) = 2 × (-2)3 + (-2)2 - 5 × (-2) + 2
= 2 × (-8 ) + (-4) - ( 10 ) + 2
= -16 + 4 -10 + 2
= -12 -10 +2
= 0
Hence proved that -2 and 1 are the zeroes of the equation 2x3 + x2 - 5x + 2
Hope so the above answer will be helpful to u
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