Question

answer this question and I will mark brainliest answer​

Answer 1

Answer:

given

then (20-3a)= tan(90-50+20)

tan(20-3a)= tan (110-5a)

20-3a= 110-5a

5a-3a=110-20

2a= 90

a=90/2{ 45

sin ascea tan a - coseca cos a cot a

= sin 45 sec 45 tan 45 - csec 45 cos 45 cot 45

= (1/√2) (√2)(1)-(√2)(1/√2)(1) =1-1=0