Question

Answer this question and I WILL MARK U AS BRAINLIEST

Two bodies P and Q of masses m and 2m are moving with velocities 2v and v respectively . Compare their :
(A) Inertia
(B) Momentum
(C) The force required to stop them in same time

Answer 1

hope this helps edits are welcome

Answer 2

"Given:

As the bodies has mass m and 2m respectively with velocities as 2v and v respectively.

Solution:

(A) Inertia:

Their inertia can be calculated by the formula of law of inertia which is totally dependent upon the bodies velocity attained as they are in motion. Thereby, the inertia of first body be more than the second as the velocity of first body is 2v. Therefore, inertia of P is more than inertia of Q.

(B) Momentum:

The momentum is product of mass and velocity.

Thereby,

Momentum of P = m 2v = 2mv

Momentum of Q is = 2m v = 2mv

(C) Force:

Therefore the momentum of P and Q are same.

Now, the force required to stop them will be same as per the Newton's second law of motion.

$F=k \frac{d p}{d t}$

$F=k \frac{\text {Change in momentum}}{\text {Change in time}}$

Where, k = 1 for all units.

Since, the momentum is same for both P and Q, we need same force to move P and Q."