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It is a question of chapter 6 class 9 ncert book right.
ST is a straight line.
∴ ∠PQR + ∠PQS = 180° …(1) [Linear pair]
Similarly, ∠PRT + ∠PRQ = 180° …(2) [Linear Pair]
From (1) and (2), we have
∠PQS + ∠PQR = ∠PRT + ∠PRQ
But ∠PQR = ∠PRQ [Given]
∴ ∠PQS = ∠PRT
Answer:
Given angle(PQR) = angle(PRS)
proof:- angle (PQS) = angle ( PRT )
Solution :-
by using exterior angle property
angle(PQS) = angle( PRQ)+ angle( RPQ).
so we can write this
angle(PQS) - angle(RPQ). = angle( PRQ). (i)
now ,
angle(PRT) = angle(PQR) + angle(QPR)
we can write this also,
angle(PRT) - angle(QPR) = angle(PQR). (ii)
according to question
angle(PQR) = angel(PRQ)
so, we can equate both (i) and (ii) equations
and we get
after equation both the equation angle(QPR) and angle(RPQ) get cancel and we get
angle (PQS) = angle (PRT)
hence proved.
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