Question

Answer this question....

Answer 2 question ​

Answer 1

Given:-

$l = 80 \: cm$

$b = 48 \: cm$

$h = 24 \: cm$

Width of tarpulin cloth:-

$width = 96 \: cm$

Formula

$\huge\bigstar\underline\mathfrak{Answer:-}$

Surface of area:-

$= 2(lb + bh + hl)$

$= 2(80 \times 48 + 48 \times 24 + 24 \times 80)$

$= 2(3840 + 1152 + 1920)$

$= 2(6212)$

$= 13824 \: cm^{2}$

$So, \: to \: find \: 100 \: cm ^{2} = 13824 \times 100$

$= 1382400 \: cm ^{2}$

Converting cm into m:-

$= 1 \div 100 \: m$

$= 1382400 \div 100$

$= 13824m$

So, Area of Tarpaulin cloth:-

$= l \times b$

$or \\ 13824 = l \times 96$

$13824 \div 96 = l$

$so \\ l = 144 ^{2}$

$so \\ 144m ^{2} is \: required \: to \: cover \: 100 \: sutcase$

Hope it helps U✌️✌️✌️...

Answer 2

Answer:144 m

Step-by-step explanation:

The suitcase

l = 80 cm

b = 48 cm

h = 24 cm

therefore,

Total Surface Area = 2(lb + bh + lh)

= 2 [(80*48) + (48*24) + (80 * 24)]

= 2 (3840 + 1152 + 1920)

= 2 * 6912

= 13824 cm^2

Length of cloth required = (area of suitcase/ breadth) * 100

= (13824/ 96) * 100

= 144 * 100

= 14400 cm

= 14400 /100 m

= 144 m