Math, asked by kapil19, 1 year ago

answer this question as soon as possible

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Answered by karthik4297
0
Given,
x = a.secФ
y = b.tanФ
secФ = x/a  
sec²Ф = (x/a)²   ------------------(i)

 tanФ = y/b
 tan²Ф =  (y/b)²   ------------(ii)
we know that,
sec²Ф - tan²Ф = 1
(x/a)² +(y/b)² = 1
(bx)² + (ay)² = a²b²

kapil19: please explain last 2 steps
karthik4297: we know the formula which is sec^2@ - tan^2@ = 1 I had used that formula and put the values of sec^2@ and tan^2@ from eqn(i) and (ii).
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