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Angle A = 80, B = 60, C = 40
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3A = 4B = 6C
3A = 4B
B = 3A/4
3A = 6C
C = 3A/6 = A/2
A + B + C = 180° (Angle sum property)
A + 3A/4 + A/2 = 180°
TAKING LCM,
(4A + 3A + 2A)/4 = 180
9A/4 = 180
A = 180×4/9
A = 80°
B = 3A/4 = 3×80/4 = 60°
C = A/2 = 80/2 = 40°
A = 80°
B = 60°
C = 40°
VERIFICATION :-
A + B + C = 80 + 40 + 60 = 180°
PLS FOLLOW....
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