Question

answer this question brainlist KR dungi✌️✌️✌️​

Answer 1

Step-by-step explanation:

Let A , B be the roots of the required equation

given A=8

AB= -56

We get B =-7

A+B =8-7 =1

THE REQUIRED POLYNOMIAL EQUATION IS

x^22-x-6

Answer 2

Given :

• One zero of a quadratic polynomial is 8
• Product of the zeroes is - 56.

To Find :

• Quadratic Polynomial

Solution :

We have the roots of the quadratic polynomial.

Let α = 8

α × β = - 56.

• Product of zero αβ :

➣ $\mathtt{\alpha\:\times\:\beta\:=\:-\:56}$

➣ $\mathtt{8\:\times\:\beta\:=\:-56}$

➣ $\mathtt{\beta\:=\:{\dfrac{-56}{8}}}$

➣ $\mathtt{\beta\:=\:-7}$

• Sum of zero α + β :

➣ $\mathtt{\alpha\:+\:\beta}$

➣ $\mathtt{8\:+\:(-7)}$

➣ $\mathtt{8-7}$

➣ $\mathtt{1}$

Using :

• x² - (α+β)x + (αβ) = 0

We can find the required quadratic polynomial.

➣ $\mathtt{x^2\:-\:(1)x\:+\:(-56)\:=\:0}$

➣ $\mathtt{x^2\:-\:x\:-56\:=\:0}$

$\large{\boxed{\mathtt{\red{ Quadratic\:polynomial\:=\:x^2\:-\:x\:-\:56\:=\:0}}}}$