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- answer : 33
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Step-by-step explanation:
Give that the no. 203 and 434 leaving remainder 5 in each case respectively.
The no. that are exactly divisible is 203- 5=198434- 5=429
Prime factorization of 198=2*3*3*11*
Prime factorization of 429 = 3*11*13.
HCF(198,429)=3*11
=33.
Therefore the largest number that divides 203 and 434 leaving remainder 5 in each case is =33.
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