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Hi friend,
x²-x/4-1/8
First, take L.C.M. of 1,4,8=8
So,
(8x²-2x-1)/8
=1/8(8x²-2x-1)
=1/8(8x²+4x-2x-1)
=1/8[4x(2x+1)-1(2x+1)]
=1/8(4x-1)(2x+1)
=(4x-1)/8(2x+1)
=(x/2-1/8)(2x+1) ANSWER...
HOPE THIS HELPS YOU:-))
x²-x/4-1/8
First, take L.C.M. of 1,4,8=8
So,
(8x²-2x-1)/8
=1/8(8x²-2x-1)
=1/8(8x²+4x-2x-1)
=1/8[4x(2x+1)-1(2x+1)]
=1/8(4x-1)(2x+1)
=(4x-1)/8(2x+1)
=(x/2-1/8)(2x+1) ANSWER...
HOPE THIS HELPS YOU:-))
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