Math, asked by 8ANONYMOUSGUY8, 1 month ago

Answer this question correctly guys plz no useless answers​

Attachments:

Answers

Answered by NewGeneEinstein
1

\boxed{\sf (a+b)^4=a4+4a^3b+6a^2b^2+4ab^3+b^4}

\\ \sf\longmapsto \left(\dfrac{x}{3}+\dfrac{2}{y}\right)^4

\\ \sf\longmapsto \left(\dfrac{x}{3}\right)^4+4\left(\dfrac{x}{3}\right)^3\dfrac{2}{y}+6\left(\dfrac{x}{3}\right)^2\left(\dfrac{2}{y}\right)^2+4\times \dfrac{x}{3}\left(\dfrac{2}{y}\right)^3+\left(\dfrac{2}{y}\right)^4

\\ \sf\longmapsto \dfrac{x^4}{3^4}+\dfrac{8}{y}\times \dfrac{x^3}{3^3}+6\times \dfrac{x^2}{3^2}\times \dfrac{2^2}{y^2}+\dfrac{4x}{3}\times \dfrac{2^3}{y^3}+\dfrac{2^4}{y^4}

\\ \sf\longmapsto \dfrac{x^4}{81}+\dfrac{8x^3}{27y}+\dfrac{24x^2}{9y^2}+\dfrac{32x}{3y^3}+\dfrac{16}{y^4}

\\ \sf\longmapsto \dfrac{x^4}{81}+\dfrac{8x^3}{27y}+\dfrac{8x^2}{3y^2}+\dfrac{32x}{3y^3}+\dfrac{16}{y^4}

Similar questions