Answer this question correctly in general solution .
please please please answer
Answers
Answered by
4
Step-by-step explanation:
Sinx + cosx = √2
sinx + cosx - √2 = 0
-√2 + sin(π/4 + x)√2 = 0
sin(π/4 + x) = √2/2
sin(π/4 + x) = 1
sin(π/4 + x) = π/2 + 2πn
x = 2πn + π/4
x = 8πn + π/4
x = (8n + 1)π/4.
Hope it helps you.
#Be brainly
Anonymous:
mark as brainliest
Answered by
2
Hi mate here is ur query..
____________
Multiplying by 1/√2 on both sides
we find
sinx(1/√2 )+cosx (1/√2 ) =1
or sinx*cos(π/4) + cosx* sin(π/4)= sin(π/2)
or sin(x+π/4) = sin(π/2)
or x+(π/4)= 2nπ+π/2
or x= 2nπ+π/4
general solution
________________
Hope this will help you.
____________
Multiplying by 1/√2 on both sides
we find
sinx(1/√2 )+cosx (1/√2 ) =1
or sinx*cos(π/4) + cosx* sin(π/4)= sin(π/2)
or sin(x+π/4) = sin(π/2)
or x+(π/4)= 2nπ+π/2
or x= 2nπ+π/4
general solution
________________
Hope this will help you.
Similar questions