Question

answer this question correctly no need to answer if you don't know ​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

area of triangle ABC=1÷2×AC×BM

$1 \div 2 \times 12 \times 6.2$

$6 \times 6.2$

$37.2$

Area of triangle ADC=

$1 \div 2 \times ac \times dn$

$1 \div 2 \times 12 \times 10.8$

$6 \times 10.8$

$64.8$

total area of quadrilateral ABCD=Area of ABC+Area of ADC

$37.2+ 64.8$

$102 {cm}^{2}$