Question

Answer this question. Cylindrical cans of cricket ball are to be packed in a box. The radius and height of each can is 8cm and 32cm respectively. The length, breadth and height of box are respectively 68cm × 52cm × 50cm. What is the maximum number of cans that can fit in the box ?
Answer this question ... please

Answer 1

Answer:

Total number of cans =6+6= 12

Step-by-step explanation:

Cylindrical cans of cricket ball are to be packed in a box. The radius and height of each can is 8cm and 32cm respectively.

here r= 8 cm

h= 32 cm

As each cylindrical can has diameter 16 cm and they can kept in verticle position and they will occupy 32 cm height of the box.

Number of such cans placed in a row

$= \frac{length}{diameter} \\ \\ = \frac{32}{16} \\ \\ = 2$

Number of such rows

$= \frac{width \: of \: box}{diameter \: of \: cans} \\ \\ = \frac{52}{16} \\ \\ ≈3$

So 2×3 = 6 verticle positions .

Now the height of the box is 50,out of which 32 cm is used,so some cans can pe but horizontally

remaining height left = 50-32=18 cm

18>16(Diameter of cans)

Number of cans in horizontal rows

$= \frac{length \: of \: box}{length \: of \: cane} \\ \\ = \frac{68}{32} \\ \\ ≈ 2$

Number of such rows

$= \frac{width \: of \: box}{diameter} \\ \\ = \frac{52}{16} \\ \\ ≈ 3$

cans horizontally placed= 3×2=6 cm

So,total number of cans =6+6= 12

Hope it helps you.

Answer 2

Answer:

Total number of cans that can be filled is 18.