^Answer This Question^
: Don't Copy Answers :
: Explaination needed :
Answers
As Anhydrous Oxalic acid is Hygroscopic in nature, it readily absorbs moisture from the air.
So, Oxalic acid in most cases is found in dihydrate condition. That is in the crystal state : C₂H₂O₄ - 2H₂O
⇒ 1 Mole of Oxalic acid in dihydrate condition weighs = (12 + 32 + 1) × 2 + (2 × 18) = 126 grams.
Given that 0.63 grams of Oxalic acid is dissolved in 250ml of water to prepare the solution.
⇒ If one Mole of Oxalic acid weighs 126 grams then we need to find how many moles of Oxalic acid makeup the weight of 0.63 grams
⇒ Number of moles which make up 0.63 grams of OA = (0.63 grams × 1 Mole)/(126 grams) = 0.005 moles.
We know that Molarity of a solution = (Number of Moles of Solute dissolved)/Volume of Solution in litres.
Here the solute is Oxalic acid and the solution is Water
250 ml of water converted into litres is 1/4 litre and we got the number of moles of solute = 0.005
Molarity of the given solution = 0.005/(1/4) = 0.005 × 4 = 0.02M
If it is mentioned in the question that Oxalic acid in Anhydrous condition is dissolved in water then we need to consider the Molar Mass of Oxalic acid as 90 grams.
⏩⏩Moles of solute = Weight / Gram Molecular weight 》》》= 0.63 g / 126 g/mol 》》》= 0.005 mol ●Volume of solution = 250 ml = 0.25 Litres ●Molarity = Moles of solute / Volume of solution in litres 》》》= 0.005 / 0.25 》》》= 0.02 Molarity of solution is 0.02 M @skb♥️