Question

answer this question exponent​

Answer 1

Answer:

y^6/4x^4

Step-by-step explanation:

Answer 2

Answer:

$(2x^2y^{-3})^{-2}$ = = $\frac{y^6}{4x^4}$

Step-by-step explanation:

Given,

$(2x^2y^{-3})^{-2}$

To find,

We need to simplify the expression

Solution:

Recall the formulas of exponents

$(ab)^m = a^mb^m$ ---------------------(A)

$a^{-m} = \frac{1}{a^m}$--------------------------(B)

$(a^m)^n = a^{mn}$-------------------------(C)

Given expression is $(2x^2y^{-3})^{-2}$

By applying formula (A) we get

= $2^{-2}(x^2)^{-2}(y^{-3})^{-2}$  

By applying the formula (C) we get

= $2^{-2}x^{2X(-2)}y^{-3X{-2}$

= $2^{-2}x^{-4}y^6$

By applying formula (B) we get

= $\frac{1}{2^2}$×$\frac{1}{x^4}$×$y^{6}$

= $\frac{y^6}{4x^4}$

∴$(2x^2y^{-3})^{-2}$ = = $\frac{y^6}{4x^4}$

#SPJ3