Question

answer this question fast​

Answer 1

$\underline{\underline{\purple{\bold{Solution \: -}}}}$

$:\sf\implies \: {2}^{3x - 1} = 256 \\ \\ :\sf\implies \: {2}^{3x - 1} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \\ \\ :\sf\implies \: {2}^{3x - 1} = {2}^{8} \\ \\ :\sf\implies \: \cancel 2^{3x - 1} = \cancel 2^{8} \\ \\ :\sf\implies \: 3x - 1 = 8 \\ \\ :\sf\implies \: 3x = 8 + 1 \\ \\ :\sf\implies \: 3x = 9 \\ \\ :\sf\implies \: \cancel \dfrac{9}{3} \\ \\ :\sf\implies \: \boxed{\bold\pink{3}} \: \bigstar$

$\sf\therefore Hence, \: the \: value \: of \: x \: is \: 3$

Answer 2

Answer :-

• Value of x = 3.

Explanation :-

Here, we are given with an equation and we have to find the value of x.

Let's Begin.

$\implies\sf{ {2}^{3x - 1} = 256 }$

Take out factors of 256.

$\small\implies\sf{ {2}^{3x - 1} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 }$

Make 256 as a power of 2.

$\implies\sf{ {2}^{3x - 1} = {2}^{8} }$

Bases are same. So, Cancel out them.

$\implies\sf{ 3x - 1 = 8 }$

Solve the equation using Transposition.

$\implies\sf{ 3x = 8 + 1 }$

Add them.

$\implies\sf{ 3x = 9 }$

Again, Use Transposition.

$\implies\sf{ x = \dfrac{9}{3} }$

Divide 9 by 3.

$\implies\underline{\boxed{\tt{\purple{ x = 3} }}}$

Therefore, Value of x = 3.