English, asked by Ameena012, 3 months ago

answer this question fast!!​

Attachments:

Answers

Answered by itzPapaKaHelicopter
4

\huge \fbox \green{❤Answer:}

Given:

central hall of a school is 18m long and 12.5m wide .a carpet is to be laid on floor leaving strip 50cm wide near walls uncovered.

To Find:

find the area of the carpet and also the uncovered portion?

\huge \fbox \pink{Solution:}

Portion \:  uncovered \:  = 50 cm = 0.5 m

Length  \: of \:  the  \: carpet = 18 m - (0.5 m + 0.5 m) = 17 m

Breadth = 12.5 m - (0.5 m + 0.5 m) = 11.5 m

Area  \: of  \: the \:  carpet = 17*11.5

= 195.5 sq m

</p><p>Area \:  of  \: the  \: hall = 18*12.5

= 225 sq m

Now area of the uncovered portion = area of the hall - area of the carpet

= 225 - 195.5

Area \:  of  \: the  \: uncovered  \: portion = 29.5 sqm

Answer:Hence,

area=225 sq.m

 and  \: Area  \: of   \\ \: the \:  uncovered  \: portion == 29.5 sqm

 \\  \\  \\  \\

 \\  \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}

Answered by cutegirl201053
5

ji Deepali ki id To batao ham bhi wish kardenge

Similar questions