Question

Answer this question fast​

Answer 1

Answer: 400 km

Explanation:

The track of the plane represents two line segments that form a right angle. The shortest distance to original position would be its hypotenuse, the length of which can be found using the Pythagorean theorem

Shortest distance = √(320² + 240²) = √(102400 + 57600)
= √160000 = 400

The shortest distance covered by plane to reach its original position is 400 km

Hope it helped

Answer 2

Answer:

• 400 Km is the required answer .

Step-by-step explanation:

According to the Question

It is given that,

Plane flies 320 Km due to West & then 240 Km due to North .

We have to calculate the shortest distance covered by the plane to reach its original position .

For calculating the shortest distance we will use here Pythagoras Theorem .

$\sf \implies \: Shortest \: distance \: = \sqrt{ {320}^{2} + {240}^{2} } \\ \\ \sf \implies \:Shortest \: distance \: = \sqrt{102400 + 57600} \\ \\ \sf \implies \: Shortest \: distance \: = \sqrt{160000} \\ \\ \sf\implies \: Shortest \: distance \: = 400 \: km$

• Hence, the shortest distance covered by the plane to reach its original position is 400Km.