Answer this question fast.
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Step-by-step explanation:
x = aSin@ and y = bSin@
x/a = Sin@ and y/b = Sin@
Do reciprocal and then Squaring and subtracting both sides
=> (a^2/x^2) - (b^2/y^2) = (1/Sin^2@) - (1/Sin^2@)
=> (a^2/x^2) - (b^2/y^2) = 0
The answer is Zero..I think ur ques is wrong...Otherwise I don't know how to Solve it for 1...
Hope it may help u
deenakhatri1974:
But the question is correct
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