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In trapesium ABCD,
side AB parallel ti side CD,
angle DCE = angle BAE,
(corresponding angles)
angle DEC = angle BEA,
(vertically opposite angles)
triangle DEC ~ triangle BEA
(AA test)
DE/EB = CE/AE
4/4x -2 = x+1/2x+4
4(2x+4) = (4x - 2)(x + 1)
8x + 16 = 4x(x + 1) -2(x + 1)
8x + 16 = 4x^2 + 4x -2x - 2
4x^2 + 4x -2x -8x = -2 + 16
4x^2 +2x - 8x = 14
4x^2 -6x - 14 = 0
2x^2 -3x - 7 =0
find x
side AB parallel ti side CD,
angle DCE = angle BAE,
(corresponding angles)
angle DEC = angle BEA,
(vertically opposite angles)
triangle DEC ~ triangle BEA
(AA test)
DE/EB = CE/AE
4/4x -2 = x+1/2x+4
4(2x+4) = (4x - 2)(x + 1)
8x + 16 = 4x(x + 1) -2(x + 1)
8x + 16 = 4x^2 + 4x -2x - 2
4x^2 + 4x -2x -8x = -2 + 16
4x^2 +2x - 8x = 14
4x^2 -6x - 14 = 0
2x^2 -3x - 7 =0
find x
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