Math, asked by Karan1114, 11 months ago

answer this question fast​

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Answered by kbalasaheb
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In trapesium ABCD,

side AB parallel ti side CD,

angle DCE = angle BAE,

(corresponding angles)

angle DEC = angle BEA,

(vertically opposite angles)

triangle DEC ~ triangle BEA

(AA test)

DE/EB = CE/AE

4/4x -2 = x+1/2x+4

4(2x+4) = (4x - 2)(x + 1)

8x + 16 = 4x(x + 1) -2(x + 1)

8x + 16 = 4x^2 + 4x -2x - 2

4x^2 + 4x -2x -8x = -2 + 16

4x^2 +2x - 8x = 14

4x^2 -6x - 14 = 0

2x^2 -3x - 7 =0
find x

kbalasaheb: mark as brainliest
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