Question

answer this question fast all questions

Answer 1

Answer:

Step-by-step explanation:

4.

Given, DE//AC and DC//AP.

In △ABC, since DE//AC, by thales theorem

BE/EC = BD/AD - (i)

Also, In △ABP, since DC//AP, by thales theorem

BC/CP = BD/AD - (ii)

From (i) and (ii),

BE/EC = BC/CP.

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