Question

answer this question fast I'll give you 10 thanks in return​

Answer 1

Answer

1) -7/2

2) 41/33

3) 35/-18

4) 129/4

5) 9

6) 2

7) 4

8) 112,72

9) 40,10

10) try yourself

Answer 2

[Answers of 5, 6, 7, 8, 9 and 10 are attached]

★ Solution (1i) :-

$\sf \leadsto \dfrac{2}{5} + \dfrac{7}{3} + \dfrac{-4}{5} + \dfrac{-1}{3}$

$\sf \leadsto \dfrac{2}{5} + \dfrac{-4}{5} + \dfrac{7}{3} + \dfrac{-1}{3}$

$\sf \leadsto \dfrac{2 - 4}{5} + \dfrac{7 - 1}{3}$

$\sf \leadsto \dfrac{-2}{5} + \dfrac{6}{3}$

$\sf \leadsto \dfrac{-6 + 30}{15}$

$\sf \leadsto \cancel \dfrac{24}{15} = \dfrac{8}{5}$

$\sf \leadsto 1 \dfrac{3}{5}$

★ Solution (1ii) :-

$\sf \leadsto \dfrac{5}{3} + \dfrac{11}{2} + \dfrac{-9}{2} + \dfrac{-8}{3} + \dfrac{-7}{2}$

$\sf \leadsto \dfrac{5}{3} + \dfrac{-8}{3} + \dfrac{11}{2} + \dfrac{-9}{2} + \dfrac{-7}{2}$

$\sf \leadsto \dfrac{5 - 8}{3} + \dfrac{11 - 9 - 7}{2}$

$\sf \leadsto \dfrac{-3}{3} + \dfrac{-5}{2}$

$\sf \leadsto \dfrac{-6 - 15}{6} = \dfrac{-21}{6}$

$\sf \leadsto \cancel \dfrac{-21}{6} = \dfrac{-7}{2}$

$\sf \leadsto -3 \dfrac{1}{2}$

★ Solution (2) :-

Let the other number be y.

$\sf \leadsto \dfrac{-5}{11} + y = \dfrac{26}{33}$

$\sf \leadsto y = \dfrac{26}{33} - \dfrac{-5}{11}$

$\sf \leadsto y = \dfrac{26 + 15}{33} = \dfrac{41}{33}$

$\sf \leadsto y = 1 \dfrac{8}{33}$

★ Solution (3) :-

Let the other number be y.

$\sf \leadsto \dfrac{-3}{14} \times y = \dfrac{5}{12}$

$\sf \leadsto y = \dfrac{5}{12} \div \dfrac{-3}{14}$

$\sf \leadsto y = \dfrac{5}{12} \times \dfrac{14}{-3}$

$\sf \leadsto y = \dfrac{70}{-36} = \dfrac{35}{-18}$

$\sf \leadsto y = -1 \dfrac{17}{18}$

★ Solution (4) :-

Let the cost of cloth per metre be y.

$\sf \leadsto 2 \dfrac{1}{3} \times y = 75 \dfrac{1}{4}$

$\sf \leadsto \dfrac{7}{3} \times y = \dfrac{301}{4}$

$\sf \leadsto y = \dfrac{301}{4} \div \dfrac{7}{3}$

$\sf \leadsto y = \dfrac{301}{4} \times \dfrac{3}{7}$

$\sf \leadsto y = \dfrac{903}{28}$

$\sf \leadsto y = 32 \dfrac{1}{4}$