Physics, asked by ramamaheshwari1983, 10 months ago

answer this question fast(if know then answer if don't then don't answer)​

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Answered by mohitgurjar59
4

Answer:

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ANSWER = \frac{ \sqrt{3} }{2}

Explanation:

Given =angle I is 60 degree

angle r is 45 degree

from Snell'law

=ua \times  \sin(60) = ub \times  \sin(45)

 =\frac{ub}{ua}  =  \frac{ \sin(60) }{ \sin(45) }  =  \frac{ \frac{ \sqrt{3} }{2} }{ \frac{1}{ \sqrt{2} } }

  =\frac{ \sqrt{3} }{2}  \times  \sqrt{2}

= \frac{ \sqrt{3} }{ \sqrt{2} }  \times  \frac{ \sqrt{2} }{ \sqrt{2} }

 = \frac{ \sqrt{3} }{2}

(a) =  \frac{ \sqrt{3} }{2}

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