Question

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Answer 1

Let the two concentric circle be C^1 and C^2 with centre O.

AB be the chord of the larger circle C^2 which touches the smaller circle C^1 at point P.

To find :- Length of AB

Solution:-

Connecting OP,OA and OB

OP = Radius of smaller circle=3 cm

OA = OB = Radius of larger circle= 5 cm

Since AB is a tangent to circle C^1

OP bisects AB

Therefore,angle OPA = angle OPB

= 90°

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Answer 2

Answer:

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Let the two concentric circle be C^1 and C^2 with centre O.

AB be the chord of the larger circle C^2 which touches the smaller circle C^1 at point P.

To find :- Length of AB

Solution:-

Connecting OP,OA and OB

OP = Radius of smaller circle=3 cm

OA = OB = Radius of larger circle= 5 cm

Since AB is a tangent to circle C^1

OP bisects AB

Therefore,angle OPA = angle OPB

= 90°

Step-by-step explanation:

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