answer this question fast please
Answers
Let the two concentric circle be C^1 and C^2 with centre O.
AB be the chord of the larger circle C^2 which touches the smaller circle C^1 at point P.
To find :- Length of AB
Solution:-
Connecting OP,OA and OB
OP = Radius of smaller circle=3 cm
OA = OB = Radius of larger circle= 5 cm
Since AB is a tangent to circle C^1
OP bisects AB
Therefore,angle OPA = angle OPB
= 90°
I just hope it will help you and if it's then please mark me as Brainlist.
Answer:
hi
good night
Let the two concentric circle be C^1 and C^2 with centre O.
AB be the chord of the larger circle C^2 which touches the smaller circle C^1 at point P.
To find :- Length of AB
Solution:-
Connecting OP,OA and OB
OP = Radius of smaller circle=3 cm
OA = OB = Radius of larger circle= 5 cm
Since AB is a tangent to circle C^1
OP bisects AB
Therefore,angle OPA = angle OPB
= 90°
Step-by-step explanation:
Please Rate My Answers And Put Thanks To My Answers And F(Follow) Me And Mark Me As Brainliest!!!!