Question

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Find the root by quadratic equation
$2x {}^{2} - 6x + 3 = 0$
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Question value 20 points each !!!​

Answer 1

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Answer 2

Answer:

x = (3 + √3)/2, (3 - √3)/2

Step-by-step explanation:

Given, Quadratic Equation is 2x² - 6x + 3 = 0.

On comparing with ax² + bx + c = 0, we get

a = 2, b = -6, c = 3.

∴ D = b² - 4ac

      = (-6)² - 4(2)(3)

      = 36 - 24

      = 12.

The solutions are:

⇒ x = -b ± √D/2a

      = -(-6) ± √12/4

      = 6 ± √12/4

      = (6 ± 2√3)/4

      = 2(3 ± √3)/4

      = (3 ± √3)/2

Therefore, the roots of the Quadratic equation are:

∴ x = (3 + √3)/2, (3 - √3)/2

Hope it helps!