Question

Answer this question for brainliest answer.

Answer 1

sorry
after
15×25/100+15×25/100=3V
3.5+3.5=3V
V=7.5/3
V=2.5mpers

Answer 2

,
$mass \: of \: first \: object = 1.5kg \\ mass \: of \: second \: object = 1.5kg \\ initial \: velocity \: of \: first \: object \: u1 = 2.5m \: s \\ initil \: velocity \: of \: second \: object \: u2 = - 2.5m \: s(because \: it \: is \: moving \: in \: opposite \: direction) \\ total \: momenta \: before \: collision = mass \: of \: first \: object \times u1 + mass \: of \: second \: object \times u2 \\ 1.5kg \times 1.5ms + 1.5kg \times - 1.5ms \\ = 3.75ms + ( - 3.75ms) \\ = 0kg \: ms \: \\ let \: final \: velocity \: be \: v \\ total \: momenta \: after \: collision \\ = (mass \: of \: 1st \: object + mass \: of \: 2nd \: object ) \times v \\ = (1.5kg + 1.5kg) \times v \\ = 3v \\ acc \: to \: law \: of \: conservation \: of \: momentum \: total \: moment a \: before \: collision = total \: momenta \: after \: collision \\ 0 = 3v \\ v = \frac{0}{3} = 0kg \: ms \\ hence \: velocity \: of \: combined \: object = 0kg \: ms$