Physics, asked by SUPERLUCKYMAN777, 1 year ago

Answer this question for brainliest answer.

Attachments:

Answers

Answered by kalpjain
4
sorry
after
15×25/100+15×25/100=3V
3.5+3.5=3V
V=7.5/3
V=2.5mpers
Attachments:

kalpjain: brainliest please please please
Answered by sahaj55
0
,
 mass \: of \: first \: object = 1.5kg \\ mass \: of \: second \: object = 1.5kg \\ initial \: velocity \: of \: first \: object  \: u1 = 2.5m \: s \\ initil \: velocity \: of \: second \: object \: u2 =  - 2.5m \: s(because \: it \: is \: moving \: in \: opposite \: direction) \\ total \: momenta \: before \: collision = mass \: of \: first \: object \times u1 + mass \: of \: second \: object \times u2  \\ 1.5kg \times 1.5ms + 1.5kg \times  - 1.5ms \\  = 3.75ms + ( - 3.75ms) \\  = 0kg \: ms \:  \\ let \: final \: velocity \: be \: v \\ total \: momenta \: after \: collision \\  = (mass \: of \: 1st \: object + mass \: of \: 2nd \: object ) \times v \\  = (1.5kg + 1.5kg) \times v \\  = 3v \\ acc \: to \: law \: of \: conservation \: of \: momentum \: total \: moment a \: before \: collision  = total \: momenta \: after \: collision \\ 0 = 3v \\ v =  \frac{0}{3}  = 0kg \: ms \\ hence \: velocity \: of \: combined \: object = 0kg \: ms
Similar questions