Question

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Answer 1

Answer:

Explanation:

Meq. of I2 used =20.10×0.05=1.005

Let meq. of As2O3 and As2O5 in mixture be a and b respectively.  

Addition of I2 to mixture converts As3+2 into As5+2.

∴ Meq. of As2O3= Meq. of I2 used =Meq. of As5+2 formed

∴a=1.005        ...(i)

After oxidation, the mixture contains all the arsenic in +5 oxidation state, which is then reduced to As3+2 by using KI and hypo.

∴ Meq. of As2O3 as As5++ Meq. of As2O3

= Meq. of I2 liberated = Meq. of hypo used

a+b=(1.113/248)×1000

or a+b=4.481           ...(ii)

By Eqs. (i) and (ii), we get b=4.481−1.005=3.476

∴ Mass of As2O3=(Meq.×Eq. mass/1000) (EAs2O3=198/4)

=1.005×198/4×1000=0.498 g

Mass of As2O5=3.476×230/4×1000(EAs2O5=230/4)

=0.1999 g

∴ Mass of mixture =0.0498+0.1999=0.2497 g