Question

^Answer this Question from the attachment with explanation^

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Answer 1

Hey sista!

Here's your answer!!

Let's assume that it reflects back with the same angle, then...

Impulse = Change in momentum

= p - (-p)

= - 2p

= -2mvCos30

$= - ( 2 \times 15 \times \frac{ \sqrt{3} }{2} )$


$= - 15 \sqrt{3} kg \: m |s$

Therefore, the impulse is - 15√3 kg m/s.

Hope it helps you!
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