Question

Answer this question guys

Answer 1

Answer:

Explanation:

Solution :-

We know that,

I(c) = 2/5MR²

Let take radius be R.

By Parallel axis theorem,

We know that,

⇒ I = I(c) + m(x)²

⇒ I = 2/5MR² + m(R)²

⇒ I = 7/5 MR²

Now, we know that,

Moment of inertia = MK²

Here, K is radius of gyration

⇒ MK² = 7/5MR²

⇒ K = √7/5R²

⇒ K = R √7/5

Hence, the radius of gyration of a uniform solid sphere about a tangent is R √7/5.