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Solution :-
Trigonometric identities used :
Cos²Φ = 1 - Sin²Φ
Sin²A Cos²B - Cos²A Sin²B = Sin²A - Sin²B
Consider LHS :
Sin²A Cos²B - Cos²A Sin²B
= Sin²A (1 - Sin²B) - (1 - Sin²A) Sin²B
= Sin²A - Sin²A Sin²B - Sin²B + Sin²A Sin²B
= Sin²A - Sin²B = RHS
Hence, Proved
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