Math, asked by Anonymous, 1 year ago



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Answered by kaushik05
4

hope this helps you☺️☺️☺️

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Answered by TheBrainliestUser
8

Solution :-

Trigonometric identities used :

Cos²Φ = 1 - Sin²Φ

Sin²A Cos²B - Cos²A Sin²B = Sin²A - Sin²B

Consider LHS :

Sin²A Cos²B - Cos²A Sin²B

= Sin²A (1 - Sin²B) - (1 - Sin²A) Sin²B

= Sin²A - Sin²A Sin²B - Sin²B + Sin²A Sin²B

= Sin²A - Sin²B = RHS

Hence, Proved

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