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Answer:
p(x)=2x³-11x²+17x-6
X=2
p(2)=2(2³)-11(2²)+17(2)-6
=2(8)-11(4)+34-6
=16-44+34-6
=0
Hence, 2 is the zero of the polynomial
x=3
p(3)=2(3³)-11(3²)+17(3)-6
=2(27)-11(9)+51-6
=54-99+51-6
=0
Hence, 3 is zero of the polynomial
x=1/2
p(1/2)=2(1/2)³-11(1/2)²+17(1/2)-6
=2(1/8)-11(1/4)+17/2-6
=1/4-11/4+17/2-6
=1/4-11/4+34/4-24/4
=0/4
=0
Hence, 1/2 is the zero of the polynomial
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