Math, asked by jhanvipatel2509, 9 months ago

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Answered by Anonymous

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❍Two particle P and Q are initially 40m apart P behind Q . Particle P starts moving with a uniform velocity 10m/s towards Q . Particle Q starting from rest has an acceleration 2ms^2 in the direction of velocity of P. Then the minimum distance between P and Q will be ?

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✐The moment Q attains the velocity of 10 m/s, the time will correspnd to the minimum distance between the ii

=> v = u + at = 10 = 0 + 2(t)

=> t = 5 s

in 5 s P moves 5x10 = 50 m towards Q & Q moves a further 5x5 = 25 m

therefore, min distance = 40 + 25 - 50 = 15 m ✍

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Answered by rumig0720

❍Two particle P and Q are initially 40m apart P behind Q . Particle P starts moving with a uniform velocity 10m/s towards Q . Particle Q starting from rest has an acceleration 2ms^2 in the direction of velocity of P. Then the minimum distance between P and Q will be ?

answer : -

The moment Q attains the velocity of 10 m/s, the time will correspnd to the minimum distance between the ii

=> v = u + at = 10 = 0 + 2(t)

=> t = 5 s

in 5 s P moves 5x10 = 50 m towards Q & Q moves a further 5x5 = 25 m

therefore, min distance = 40 + 25 - 50 = 15 m

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