Question

Answer this question in complete steps​

Answer 1

n(A) = m

n(B) = k

n(P(A)) = 2^m

n(P(B)) = 2^k

n(P(A)) / n(P(B)) = 64 / 1 = 2^m / 2^k

2^(m-k) = 64 = 2^6

2^(m-k) = 2^6

m - k = 6 - (1)

n(A) + n(B) = m + k = 12 - (2)

solving 1 and 2 we get,

m + n = 12

+ m - n = 6

2m = 18

m = 9

Therefore,

k = 3 ( from (2) )

Hope it helps GG.

Answer 2

n(A) = m

n(B) = k

n(P(A)) = 2^m

n(P(B)) = 2^k

n(P(A)) / n(P(B)) = 64 / 1 = 2^m / 2^k

2^(m-k) = 64 = 2^6

2^(m-k) = 2^6

m - k = 6 - (1)

n(A) + n(B) = m + k = 12 - (2)

solving 1 and 2 we get,

m + n = 12

+ m - n = 6

2m = 18

m = 9

Therefore,

k = 3 ( from (2) )

Hope it helps Gaurav gupta