answer this question it's urgent
Answers
Step-by-step explanation:
Given :-
Area of a square is (4X+12√XY + 9Y)
To find :-
Find its perimeter ?
Solution :-
Given that
Area of a square is (4X+12√XY + 9Y) sq.units
We know that
X = (√X)²
Y =(√Y)²
Now it becomes
=> [4(√X)²+12√XY+9(√Y)²]
=> [2²(√X)²+12√XY+3²(√Y)²]
=> [(2√X)²+12√XY+(3√Y)²]
=> [(2√X)²+(2×2×3√XY)+(3√Y)²]
=> [(2√X)²+(2×2√X×3√Y)+(3√Y)²]
This is in the form of a²+2ab+b²
Where, a = 2√X and b = 3√Y
We know that
(a+b)² = a²+2ab+b²
[(2√X)²+(2×2√X×3√Y)+(3√Y)²]
=> [ 2√X+3√Y]²
Area of the square = ( 2√X+3√Y) ² sq.units
We know that
Area of a square whose side is a units is a² sq units
=> a² = ( 2√X+3√Y) ²
=> a = (2√X+3√Y) units
The side of the square = (2√X+3√Y) units
Now
We know that
Perimeter of a square whose its side a units
= 4a units
Perimeter of the given square
=> 4×(2√X+3√Y) units
=> [(4(2√X)+(4×3√Y) ] units
=> (8√X+12√Y) units
Answer:-
Perimeter of the given square is (8√X+12√Y) units
Used formulae:-
→ Area of a square whose side is a units
= a² sq units
→ Perimeter of a square whose its side a units
= 4a units
Answer:
SEE THE IMAGE FOR SOLUTION
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