answer this question no. 10
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(10).
Given 1st term a = 1.
Last term l = 20.
Sum (sn) = 399.
We know that sum of n terms of an AP is given by:
= > sn = (n/2)(a + l)
= > 399 = (n/2)(1 + 20)
= > 399 * 2 = 21n
= > 798 = 21n
= > n = 38.
Therefore the value of n = 38.
Hope this helps!
Given 1st term a = 1.
Last term l = 20.
Sum (sn) = 399.
We know that sum of n terms of an AP is given by:
= > sn = (n/2)(a + l)
= > 399 = (n/2)(1 + 20)
= > 399 * 2 = 21n
= > 798 = 21n
= > n = 38.
Therefore the value of n = 38.
Hope this helps!
siddhartharao77:
:-)
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