Question

Answer this question. No explanation answer will be reported!! Refer to this image​

Answer 1

Provided that:

• Initial velocity = 0 m/s
• Height = 3 m
• Acceleration = 5 m/s sq.

To calculate:

• Final velocity

Solution:

• Final velocity = 5.47 m/s

Using concept:

• Third equation of motion

Using formula:

• 3rd eqⁿ of motion → v² - u² = 2as

Required solution:

→ v² - u² = 2as

→ v² - (0)² = 2(5)(3)

→ v² - 0 = 10 · 3

→ v² = 30

→ v = √30

→ v = 5.47 metre per second

→ Final velocity = 5.47 m/s $\:$

Answer 2

➤ Answer

• Final velocity of the wooden slab = 5.47 m/s.

➤ Given

• Initial velocity = 0 m/s.
• Distance travelled = 3 meter.
• Acceleration = 5m/s².

➤ To Find

• The final velocity of the wooden slab.

➤ Step By Step Explanation

➠ By using third equation of motion

• v² - u² = 2as

➠ By substituting the values

$\longmapsto\tt {v}^{2} - {u}^{2} = 2as \\ \\\longmapsto\tt {v}^{2} - {0}^{2} = 2 \times 5 \times 3 \\ \\ \longmapsto\tt {v}^{2} = 30 \\ \\\longmapsto\tt v = \sqrt{30} \\ \\\longmapsto\bf{\green{v = 5.47\:m/s}}$

➵ Therefore, final velocity of the wooden slab = 5.47m/s.

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➤ Equations of motion

There are mainly three equations of motion. They are as follows -

• v = u + at
• s = ut + ½at²
• v² - u² = 2as

Where, u = initial velocity , v = final velocity, t = time, a = acceleration, and s = distance travelled.

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