Question

Answer this question ..
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Answer 1

$\sf \Large Solution!!$

$\sf \to \dfrac{4x+17}{18}-\dfrac{13x-2}{17x-32}+\dfrac{x}{3}=\dfrac{7x}{12}-\dfrac{x+16}{36}$

$\sf \to \dfrac{4x+17}{18}+\dfrac{x}{3}-\dfrac{7x}{12}+\dfrac{x+16}{36}=\dfrac{13x-2}{17x-32}$

$\sf \to \dfrac{8x+34+12x-21x+x+16}{36}=\dfrac{13x-2}{17x-32}$

$\sf \to \dfrac{\cancel{-21x}\cancel{+21x}+34+16}{36}=\dfrac{13x-2}{17x-32}$

$\sf \to \dfrac{25}{18}=\dfrac{13x-2}{17x-32}$

Cross-multiplication

25(17x - 32) = 18(13x - 2)

425x - 800 = 234x - 36

425x - 234x = -36 + 800

191x = 764

x = 764 ÷ 191

$\boxed{\boxed{\sf \blue{\large x=4}}}$

Answer 2

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