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4.) If α and β are zeroes of quadratic polynomial than the quadratic polynomial is given by k ( x² - ( α + β ) x + αβ )
where , ( α + β ) is sum of zeroes and αβ is product of zeroes.
Here, α = - 3 and β = 2
⇒ α + β = -3 + 2 = -1
αβ = -3 × 2 = -6
⇒ Quadratic Polynomial = k ( x² - ( -1 ) x + ( -6 ) )
= k ( x² + 1x - 6 )..
Therefore, Quadratic Polynomial is k ( x² + 2x - 8 )
5.) the answer is 0.
6.) 5x-4y+8=0
7x+6y-9=0
a1/a2=5/7
b1/b2=-4/6=-2/3
a1/a2 is not equal to b1/b2.
It has unique solution..
Therefore lines will intersect each other..
Hope it helps you my friend
hicky52728:
circles have infinity tangent
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