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According to the question after time 2h
300=(v+7)2+34+v2 [dist= velocity× time]
300=2v+14+34+2v
300=4v+48
4v=252
v=63 km/h
Check: Put v=63 in the equation then RHS converts to
(63+7)2+34+63×2
70×2+34+63×2
140+34+126
300
Which is equal to LHS.
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