Math, asked by SSU, 11 months ago

Answer this..... question number 9

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Answered by abdul9838

$<b> <body \: bgcolor = "skyblue">$

$\bf \pink{hey \: user \: here \: is \: answer \: } \\ \\ \bf \blue{ \huge \: solution} \\ \\ \:\bf \purple{ \underline{ \underline{according \: to \: question}}} \\ \\ \bf \pink{\frac{4}{x} + 3y = 8} \\ \\ \\ \bf \pink{ \frac{4 + 3xy}{x} = 8 }\\ \\\bf \pink{4 + 3xy = 8x} \\ \\ \bf \pink{4 = 8x - 3xy}\\ \\\bf \pink{x(8 - 3y) = 4} \\ \\ \bf \pink{x = \frac{4}{8 - 3y} - - - equation \: 1st }\\ \\\bf \pink{and} \\ \\ \bf \pink{ \frac{6}{x} - 4y = - 5} \\ \\ \bf \pink{ \frac{6 - 4xy}{x} = - 5} \\ \\ \bf \pink{ - 5x = 6 - 4xy} \\ \\ \bf \pink{4xy - 5x = 6} \\ \\ \bf \pink{x(4y - 5) = 6} \\ \\ \bf \pink{x = \frac{6}{4y - 5} } \\ \\ \bf \purple{putting \: the \: value \: of \: x} \\ \\ \bf \pink{ \frac{4}{8 - 3y} = \frac{6}{4y - 5} } \\ \\ \bf \pink{6(8 - 3y) = 4(4y - 5)} \\ \\ \bf \pink{48 - 18y = 16y - 20} \\ \\ \bf \pink{48 + 20 = 16y + 18y} \\ \\ \bf \pink{68 = 34y} \\ \\ \bf \pink{y = \frac{68}{34} } \\ \\ \bf \pink{y = 2 } \\ \\ \bf \pink{putting \: the \: value \: of \: y \: in \: equation \: 1st} \\ \\ \bf \pink{x = \frac{4}{8 - 3y} } \\ \\ \bf \pink{x = \frac{4}{8 - 3 \times 2} } \\ \\ \bf \pink{x = \frac{4}{8 - 6} } \\ \\ \bf \pink{x = \frac{4}{2} } \\ \\ \bf \pink{x = 2} \\ \\ \bf \pink{so \: answer \: is \: } \\ \bf \pink{x = 2} \\ \bf \pink{and} \\ \bf \pink{y = 2} \: \: answer$

Answered by Anonymous

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tHE ABOVE ANSWER IS TOTALLY CORRECT

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Answer this..... question number 9