Answer this question of Vectors!
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IA+BI = IA-BI
√A² + B²+ AB cos (A,B) = √A²+B²-AB cos (A,B)
on s o b s
A² + B²+ ABcos ( A,B) = A²+ B²- AB cos (A,B)
AB cos (A,B) = - AB cos (A,B)
cos (A,B) + cos (A,B) = 1
2cos (A,B)=1
cos (A,B)= 1/2
cos (A,B) = cos pi by two
cos(A,B) = cos 90°
(A,B) = 90°
therefore, the angle between two vectors is 90° and those two vectors are perpendicular to each other.
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--------------------------------------*thank you*--------------------------------------------
√A² + B²+ AB cos (A,B) = √A²+B²-AB cos (A,B)
on s o b s
A² + B²+ ABcos ( A,B) = A²+ B²- AB cos (A,B)
AB cos (A,B) = - AB cos (A,B)
cos (A,B) + cos (A,B) = 1
2cos (A,B)=1
cos (A,B)= 1/2
cos (A,B) = cos pi by two
cos(A,B) = cos 90°
(A,B) = 90°
therefore, the angle between two vectors is 90° and those two vectors are perpendicular to each other.
Hope this answer is helpful for u. If so then plz mark it as abrainlist answer.
--------------------------------------*thank you*--------------------------------------------
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Answer:90degrees
Explanation:
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